1/(x-3)+1/(x+3)=10/(x^2-9)

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Solution for 1/(x-3)+1/(x+3)=10/(x^2-9) equation:


D( x )

x-3 = 0

x^2-9 = 0

x+3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

1/(x-3)+1/(x+3) = 10/(x^2-9) // - 10/(x^2-9)

1/(x-3)+1/(x+3)-(10/(x^2-9)) = 0

1/(x-3)+1/(x+3)-10*(x^2-9)^-1 = 0

1/(x-3)+1/(x+3)-10/(x^2-9) = 0

(1*(x+3)*(x^2-9))/((x-3)*(x+3)*(x^2-9))+(1*(x-3)*(x^2-9))/((x-3)*(x+3)*(x^2-9))+(-10*(x-3)*(x+3))/((x-3)*(x+3)*(x^2-9)) = 0

1*(x+3)*(x^2-9)+1*(x-3)*(x^2-9)-10*(x-3)*(x+3) = 0

2*x^3-10*x^2-18*x+90 = 0

2*x^3-10*x^2-18*x+90 = 0

2*(x^3-5*x^2-9*x+45) = 0

x^3-5*x^2-9*x+45 = 0

{ 1, -1, 3, -3, 5, -5, 9, -9, 15, -15, 45, -45 }

1

x = 1

x^3-5*x^2-9*x+45 = 32

1

-1

x = -1

x^3-5*x^2-9*x+45 = 48

-1

3

x = 3

x^3-5*x^2-9*x+45 = 0

3

x-3

x^2-2*x-15

x^3-5*x^2-9*x+45

x-3

3*x^2-x^3

45-2*x^2-9*x

2*x^2-6*x

45-15*x

15*x-45

0

x^2-2*x-15 = 0

DELTA = (-2)^2-(-15*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+2)/(1*2) or x = (2-64^(1/2))/(1*2)

x = 5 or x = -3

x in { -3, 5, 3}

2*(x+3)*(x-5)*(x-3) = 0

(2*(x+3)*(x-5)*(x-3))/((x-3)*(x+3)*(x^2-9)) = 0

(2*(x+3)*(x-5)*(x-3))/((x-3)*(x+3)*(x^2-9)) = 0 // * (x-3)*(x+3)*(x^2-9)

2*(x+3)*(x-5)*(x-3) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-3 )

x-3 = 0 // + 3

x = 3

( x-5 )

x-5 = 0 // + 5

x = 5

x in { -3}

x in { 3}

x = 5

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